1(iv)
A sequence of DNA has 300 nitrogenous base pairs, of which 75 are Guanine. What is the number of Thymine in this sequence ?
- (a)150
- (b)100
- (c)50
- (d)75
Show SolutionHide Solution↓
75
Reason
If Guanine = 75, then cytosine = 75
So, Guanine + Cytosine = 75 + 75 = 150
Remaining bases = 300 - 150 = 150
Adenine + Thymine = 150
Since, Adenine = Thymine
So, we will divide 150 equally between them.
150/2 = 75
So, Adenine = Thymine = 75