(i) Calculate:

(i) Gram molecular mass of oxygen = 32 g = 1 mole

32 g = 1 mole

∴ 12 g = $\frac{1}{32}$ x 12 = 0.375 moles.

6 x 10²³ atoms of carbon weigh = 12 g

∴ 10²² atoms of carbon will weigh = $\frac{12}{ 6\times 10^{23}}$ x 10²² = 0.2 g.

Hence, number of moles = 0.375 moles and weight of 10²² atoms of carbon = 0.2 g.

(ii) Molecular formula of the compound is C₆H₁₈O₃

Molecular formula = n x (Empirical Formula)

C₆H₁₈O₃ can be written as 3(C₂H₆O)

∴ Molecular formula = 3 x (C₂H₆O)

∴ Empirical Formula of the compound is C₂H₆O