1(v)
The diagram given below shows that P reacts with dilute hydrochloric acid to produce a gas which when passed through substance Q, reduces it.
What are substances P and Q?
- (a)P - copper, Q - lead (II) oxide
- (b)P - lead, Q - magnesium oxide
- (c)P - magnesium, Q - calcium oxide
- (d)P - zinc, Q - copper (II) oxide
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P - zinc, Q - copper (II) oxide
Reason — Zinc reacts with dilute hydrochloric acid to liberate hydrogen gas. Hydrogen is a reducing agent, so on passing over heated copper(II) oxide it reduces the black oxide to reddish-brown copper.
Zn + 2HCl ⟶ ZnCl2 + H2
CuO + H2 ⟶ Cu + H2O