Model Question Paper

ICSE Class 9 Chemistry · Selina Solutions Concise Chemistry Class 9 ICSE · 88 solved questions

Exercise
1(i)Section A

Water is a polar covalent compound. It dissolves :

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All of these

Reason — Water dissolves many substances, forming aqueous solutions (water solutions). Not only solids but gases and other liquids can also dissolve in water to a large extent. For the same reason, water is called a universal solvent.

1(ii)Section A

The relationship between pressure and volume at constant temperature is given by :

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Boyle

Reason — According to Boyle's law volume of a given mass of a dry gas is inversely proportional to its pressure at constant temperature.

P1V1 = P2V2

1(iii)Section A

The chemical reaction in which heat is evolved is known as:

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Exothermic reaction

Reason — A chemical reaction in which heat is given out is called an exothermic reaction. It causes a rise in temperature.

1(iv)Section A

The molecular formula of ammonium phosphate is:

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(NH4)3PO4

Reason — The molecular formula of ammonium phosphate is (NH4)3PO4

1(v)Section A

If an element has five electrons in its outermost shell, then it is likely to be:

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Non metallic

Reason — Element with five electrons in its outermost shell, will lie in 15 A group of periodic table and will be a non-metal.

1(vi)Section A

The double covalent molecule is :

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Oxygen

Reason — To attain the stable electronic configuration of the nearest noble gas neon, oxygen needs two electrons.
When two oxygen atoms come closer, each contributes two electrons and so they have two shared pair of electrons between them. Both atom attain an octet, resulting in the formation of a double covalent bond [O=O] between them.

1(vii)Section A

According to modern periodic law, the properties of elements are a periodic function of their:

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Atomic number

Reason — According to modern periodic law, the properties of elements are a periodic function of their atomic number.

1(viii)Section A

Which of the following will produce water vapour on heating?

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Washing soda crystals

Reason — Washing soda crystals (Na2CO3.10H2O) contain water of crystallisation. On heating, it is given off as water vapour.

1(ix)Section A

The gas which produces a black precipitate when passed through lead acetate solution is:

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Hydrogen sulphide

Reason — When hydrogen sulphide is passed through lead acetate solution, it produces a silvery black precipitate of PbS.

1(x)Section A

When acid reacts with base to form salt and water only, the reaction is known as:

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Neutralisation

Reason — The reaction between an acid and a base that forms salt and water only is referred to as Neutralisation reaction.

1(xi)Section A

The graph of PV vs P for a gas is:

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A straight line parallel to X axis

Reason — a straight line is obtained parallel to the pressure axis.

1(xii)Section A

Which metal gives hydrogen upon reaction with all of the following - Acid, alkali, water?

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Zinc

Reason — Zn has a unique nature.

Zinc is considered to have a unique nature because it can react with acids and can even react with hot conc. alkalis to form hydrogen and a soluble salt.

Zn + 2HCl ⟶ ZnCl2 + H2

Zn + 2NaOH ⟶ Na2ZnO2 + H2 ↑

Zn with water also gives hydrogen

Zn + H2O ⟶ ZnO + H2

1(xiii)Section A

A gas which can act as an oxidizing as well as reducing agent:

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SO2

Reason — Sulphur dioxide is an oxidizing as well as reducing agent.

1(xiv)Section A

Isotopes differ in number of :

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Neutrons

Reason — Isotopes are the elements having the same atomic number but different mass numbers.

For example : 2412Mg and 2612Mg

Isotopes differ in number of neutrons.

1(xv)Section A

The substance which leaves a black residue on heating is :

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Copper nitrate

Reason — Copper nitrate on heating gives black residue of copper oxide and nitrogen dioxide gas along with oxygen gas are evolved.

2(a)Section A

Name the gas evolved in each of the following cases:

(i) Copper carbonate is heated strongly

(ii) Lead nitrate is heated

(iii) Nitrogen combines with hydrogen

(iv) Copper sulphate is heated strongly

(v) Addition of sodium to cold water

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(i) Carbon dioxide [CO2]

(ii) Nitrogen dioxide [NO2] and oxygen gas [O2]

(iii) Ammonia [NH3]

(iv) Sulphur dioxide [SO2] and oxygen gas [O2]

(v) Hydrogen gas [H2]

2(b)Section A

What do you observe when :

(i) Ammonium chloride crystals are heated in a test tube ?

(ii) Iron nails are added to copper sulphate solution ?

(iii) Lead nitrate crystals are heated strongly?

(iv) Silver nitrate solution is mixed with sodium chloride solution?

(v) Blue copper sulphate crystals are heated ?

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(i) On heating ammonium chloride, white crystalline solid sublimates to form a basic gas (NH3) and acidic gas (HCl). The dense white fumes are noticed that form a white mass on the cooler parts of the test tube. No residue is left behind.

(ii) When iron nail is kept in a blue coloured copper sulphate solution for sometime, a reddish brown coating is seen on the iron nail and the colour of the solution changes gradually from blue to light green. The reason for this observation is that iron being more reactive than copper, displaces copper from the solution and copper is deposited on the iron nail

(iii) When solid lead nitrate is heated strongly, it decomposes to produce light yellow solid lead monoxide, reddish brown nitrogen dioxide gas and colourless oxygen gas.

(iv) When silver nitrate solution is mixed with sodium chloride solution, a white ppt of silver chloride is formed along with sodium nitrate.

(v) The blue coloured hydrous copper sulphate changes to white anhydrous copper sulphate releasing water of crystallization.

2(c)Section A

(i) Define : Relative atomic mass.

(ii) Why is it necessary to balance a chemical equation ?

(iii) Calculate the percentage of nitrogen in ammonium phosphide. (At.wt. : N = 14, P = 31, O = 16)

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(i) The number of times one atom of an element is heavier than $\frac{1}{12}$th the mass of an atom of carbon [C12] is known as the Relative Atomic Mass [RAM] of the element.

(ii) An equation must be balanced in order to comply with the "Law of Conservation of Matter", which states that matter is neither created nor destroyed in the course of a chemical reaction. An unbalanced equation would imply that atoms have been created or destroyed.

(iii) Molar mass of ammonium phosphide [(NH4)3PO4]

= 3[14 + 4(1)] + 31 + 4(16)]

= 3[18] + 31 + 64

= 54 + 31 + 64

= 149 g

Mass of nitrogen in one mole of ammonium phosphide = 3 x 14 = 42 g

149 g of ammonium phosphide contains 42 g of nitrogen.

∴ 100 g of ammonium phosphide contains $\frac{42 \times 100 }{149}$ = 28.18% of nitrogen.

2(d)Section A

(i) Balance each of the following chemical equations :

  1. FeCl3 + NH4OH ⟶ NH4Cl + Fe(OH)3

  2. Zinc + Nitric acid ⟶ Zinc nitrate + Nitrogen dioxide + Water

(ii) Identify the substance which matches the description given below:

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(i) 1. FeCl3 + 3NH4OH ⟶ 3NH4Cl + Fe(OH)3

  1. Zn + 4HNO3 ⟶ Zn(NO3)2 + 2NO2 + 2H2O

(ii) 1. Ammonium chloride [NH4Cl]

  1. Copper
2(e)Section A

Define or explain the following terms :

(i) Absolute temperature

(ii) Valency

(iii) Ozone depletion

(iv) Electrovalent bond

(v) Atom

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(i) Absolute temperature — The temperature on the Kelvin scale at which molecular motion completely ceases is called absolute zero. Absolute zero is -273°C.

(ii) Valency — Valency is the combining capacity of an atom of an element or of a radical with the atoms of other elements or radicals to form molecules.

(iii) Ozone depletion — Ozone layer depletion is the thinning of the ozone layer present in the upper atmosphere. This happens when the chlorine and bromine atoms in the atmosphere come in contact with ozone and destroy the ozone molecules

(iv) Electrovalent bond — The chemical bond formed between two atoms by transfer of one or more electrons from the atom of a metallic (electropositive) element to an atom of a non-metallic (electronegative) element is called ionic bond or electrovalent bond.

(v) Atom — An atom is the smallest particle of an element that exhibits all the properties of that element. It may or may not exist independently but takes part in every chemical reactions.

3(a)Section B

The formula of the chloride of the metal 'M' is MCl3. State the formula of its:

(i) Carbonate

(ii) Hydroxide

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(i) Formula of metal carbonate

$$\begin{aligned}\text{M}^{3+} \phantom{\nearrow} \text{CO}_{3}^{2-} \\[0.5em] \overset{\phantom{3}{3}}{\text{M}} \space {\searrow}\mathllap{\swarrow} \space \overset{2}{\text{C}}\text{O}_{3} \Rightarrow \underset{\phantom{2}{2}}{\text{M}} \space {\searrow}\mathllap{\swarrow} \space \underset{3}{\text{C}}\text{O}_{3} \\[0.5em]\end{aligned}$$

So, we get the formula as $\bold{M}_{\bold{2}}\bold{(CO_{\bold{3}}})_{\bold{3}}$

(ii) Formula of metal hydroxide

$$\begin{aligned}\text{M}^{3+} \phantom{\nearrow} \text{OH}^{1-} \\[0.5em] \overset{\phantom{3}{3}}{\text{M}} \space {\searrow}\mathllap{\swarrow} \space \overset{1}{\text{OH}} \Rightarrow \underset{\phantom{2}{1}}{\text{M}} \space {\searrow}\mathllap{\swarrow} \space \underset{3}{\text{OH}} \\[0.5em]\end{aligned}$$

So, we get the formula as $\bold{M}\bold{(OH)}_{\bold{3}}$

3(b)Section B

Name the kind of particles (ions or molecules) present in:

(i) Sodium chloride

(ii) Carbon tetrachloride

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(i) Contains ions only

(ii) Contains only molecules

3(c)Section B

Draw the orbital structure of each of the following compounds:

(i) Water

(ii) Magnesium chloride

[At.No. : H = 1, 0 = 16, Mg = 12, Cl = 17]

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(i) Orbital structure of water molecule is shown below :

Draw the atomic orbit structure diagram for formation of a water molecule. Chemical Bonding, Simplified Chemistry Dalal Solutions ICSE Class 9

(ii) Orbital structure of Magnesium chloride molecule is shown below :

Give orbital diagram of Magnesium Chloride. Atomic Structure and Chemical Bonding, Concise Chemistry Solutions ICSE Class 9.
3(d)Section B

Write a balanced chemical equation for each of the following reactions:

(i) Magnesium hydrogen carbonate reacts with slaked lime.

(ii) Formation of coloured precipitate.

(iii) Heating ammonium dichromate.

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(i) Magnesium hydrogen carbonate reacts with slaked lime.

Mg(HCO3)2 + Ca(OH)2 ⟶ MgCO3↓ + CaCO3↓ + 2H2O

(ii) Formation of coloured precipitate.

3NaOH + FeCl3 ⟶ Fe(OH)3 [reddish brown ppt.] + 3NaCl

(iii) Heating ammonium dichromate.

$\underset{\text{[Ammonium dichromate (orange)]}}{(\text{NH}_4)_2\text{Cr}_2\text{O}_7} \xrightarrow{\space \Delta \space} \underset{\text{ [Chromic oxide(green)]}}{\text{Cr}_2\text{O}_3} + 4\text{H}_2\text{O} + \text{N}_2$

4(a)Section B

Write 2 points of comparison between Halogens and Alkali metals.

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PropertyHalogensAlkali metals
NatureHighly reactive, highly electronegative, non-metalsHighly reactive, highly electropositive, light soft metals
Reducing / Oxidizing natureStrong oxidizing agentsStrong reducing agents
4(b)Section B

Give one equation each to show the reactions of sulphuric acid :

(i) with a metal carbonate

(ii) with a metal

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(i) Na2CO3 + H2SO4 ⟶ Na2SO4 + H2O + CO2 ↑

(ii) Mg + H2SO4 (dil.) ⟶ MgSO4 + H2 ↑

4(c)Section B

(i) State Boyle's law.

(ii) Calculate the volume occupied by 2 g of hydrogen at 270°C and 4 atmosphere pressure if at STP it occupies 22.4 litres.

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(i) Boyle's law — Temperature remaining constant the volume of a given mass of dry gas is inversely proportional to it's pressure.

V ∝ $\frac{1}{\text{P}}$ [T = constant]

(ii) Initial conditions [S.T.P.] :

P1 = Initial pressure of the gas = 1 atm

V1 = Initial volume of the gas = 22.4 l

T1 = Initial temperature of the gas = 273 K

Final conditions :

P2 (Final pressure) = 4 atm

T2 (Final temperature) = 270°C = 270 + 273 = 543 K

V2 (Final volume) = ?

By Gas Law:

$\frac{\text{P}_1\times\text{V}_1}{\text{T}_1} = \frac{\text{P}_2\times\text{V}_2}{\text{T}_2}$

Substituting the values :

$$\begin{aligned}\frac{1 \times 22.4}{273} = \frac{4 \times \text{V}_2}{543} \\[1em] \text{V}_2 = \frac{543 \times 22.4}{273 \times 4} \\[1em] \text{V}_2 = \frac{12163.2}{1092} \\[1em] \text{V}_2 = 11.13 \text{ l} \\[1em]\end{aligned}$$

∴ Volume occupied = 11.13 l

4(d)Section B

Part of the periodic table is shown as :

H            He
LiBeBCNOFNe
NaMgAlSiPSClAr
KCa         

Based on the above table, name the :

(i) Element with duplet

(ii) Lightest alkali metal

(iii) Halogen of period 2

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(i) He

(ii) Li

(iii) F

5(a)Section B

What is an acid rain ?

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The term 'acid rain' refers to all precipitations — rain, snow, fog, dew — that are more acidic than normal water (i.e., have pH less than 5.6, the pH value of normal water).

5(b)Section B

How does acid rain affect soil chemistry and water bodies?

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Acid rain affects soil chemistry. It removes calcium and potassium, both the basic ingredients of soil, thus making it lose its fertility.

Acid rain has serious ecological impacts as it affects water bodies too. The water of lakes and rivers is gradually becoming acidic due to acid rain, which is affecting aquatic life.

5(c)Section B

Name the first three halogens. Give their physical state and colour.

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ElementPhysical stateColour
Fluorine (F)GasPale yellow
Chlorice (Cl)GasGreenish yellow
Bromine (Br)LiquidReddish brown
5(d)Section B

A heavy crystalline white solid on heating in a test tube crumbles with a crackling sound and gives a reddish brown residue which changes to yellow and partly fuses with the glass and stains it yellow. A brown gas is also evolved. A glowing wooden splinter relights when held near the products evolved.

(i) Name the brown gas evolved.

(ii) What is the residue left in the test tube?

(iii) Write the formula of the crystalline white solid.

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(i) Nitrogen dioxide

(ii) Lead (II) oxide (PbO)

(iii) Pb(NO3)2 (Lead (II) nitrate)

6(a)Section B

Distinguish between the following pairs of substances :

(i) Sodium sulphide and sodium sulphite

(ii) HCl gas and chlorine gas

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(i) On addition of dil. sulphuric acid to sodium sulphide, hydrogen sulphide (H2S) gas is evolved which can be identified by its rotten egg smell. Hydrogen sulphide gas turns moist lead acetate paper silvery black.

Na2S + H2SO4 ⟶ Na2SO4 + H2S ↑

On addition of dil. sulphuric acid to sodium sulphite, sulphur dioxide (SO2) gas is evolved. Sulphur dioxide gas has a suffocating odour and turns lime water milky and potassium permanganate solution from pink to clear colourless.

Na2SO3 + H2SO4 (dil.) ⟶ Na2SO4 + H2O + SO2↑

(ii) HCl and chlorine gas

Chlorine (Cl2) turns moist starch iodide paper blue black whereas HCl does not.

Cl2 + 2KI ⟶ 2KCl + I2

Starch + I2 ⟶ Blue black colour

6(b)Section B

Al2O3 is the formula of Aluminium oxide. Write the formulae of :

(i) Aluminium nitrate

(ii) Aluminium phosphate

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(i) Formula of aluminium nitrate

$$\begin{aligned}\text{Al}^{3+} \phantom{\nearrow} \text{NO}_{3}^{1-} \\[0.5em] \overset{\phantom{3}{3}}{\text{Al}} \space {\searrow}\mathllap{\swarrow} \space \overset{1}{\text{N}}\text{O}_{3} \Rightarrow \underset{\phantom{2}{1}}{\text{Al}} \space {\searrow}\mathllap{\swarrow} \space \underset{3}{\text{N}}\text{O}_{3} \\[0.5em]\end{aligned}$$

So, we get the formula as $\bold{Al}\bold{(NO}_{\bold{3}}\bold{)}_\bold{3}$

(ii) Formula of aluminium phosphate

$$\begin{aligned}\text{Al}^{3+} \phantom{\nearrow} \text{PO}_{4}^{3-} \\[0.5em] \overset{\phantom{3}{3}}{\text{Al}} \space {\searrow}\mathllap{\swarrow} \space \overset{3}{\text{P}}\text{O}_{4} \Rightarrow \underset{\phantom{2}{1}}{\text{Al}} \space {\searrow}\mathllap{\swarrow} \space \underset{1}{\text{P}}\text{O}_{4} \\[0.5em]\end{aligned}$$

So, we get the formula as $\bold{Al}\bold{PO}_{\bold{4}}$

6(c)Section B

The electronic configuration of three elements A, B and C are as follows :

A — 2, 8, 8, 2;

B — 2, 8, 7

C — 2, 4

(i) Which of these can form cations ?

(ii) Which of these can form anions ?

(iii) Write a formula of a covalent compound formed using these elements

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(i) A will form cations as it will lose electrons to attain a stable octet.

(ii) B will form anions as it will gain electrons to attain a stable octet.

(iii) Formula of a covalent compound formed

$$\begin{aligned}\text{C}^{4} \phantom{\nearrow} \text{B}^{1-} \\[0.5em] \overset{\phantom{3}{4}}{\text{C}} \space {\searrow}\mathllap{\swarrow} \space \overset{1}{\text{B}} \Rightarrow \underset{\phantom{2}{1}}{\text{C}} \space {\searrow}\mathllap{\swarrow} \space \underset{4}{\text{B}} \\[0.5em]\end{aligned}$$

So, we get the formula as $\bold{CB}_{\bold{4}}$

6(d)Section B

(i) What do you understand by the term 'isotopes'?

(ii) Why do isotopes of an element possess identical chemical properties ?

(iii) Name the isotope of hydrogen which do not have a neutron in it.

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(a) The atoms of the same element, having same atomic number (Z), but different mass number (A), are called isotopes.

​(ii) Chemical properties of isotopes of the same element are similar because chemical properties are dependent on the electronic configuration of an atom. As Isotopes have same atomic number so they have same number of electrons and hence same electronic configuration.

(iii) Protium (11H).

7(a)Section B

(i) Why is it necessary to compare gases at STP ?

(ii) What are the STP conditions ?

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(i) Since volume of a gas changes remarkably with change in temperature and pressure, it becomes necessary to choose standard values of temperature and pressure to which gas volumes can be referred.

(ii) The standard values chosen are 0°C or 273 K for temperature and 1 atm or 760 mm of Hg for pressure. These values are known as standard temperature and pressure (STP).

7(b)Section B

What temperature in degree centigrade would be necessary to double the volume of a gas (initially at STP), if the pressure is reduced to half ?

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Initial conditions [S.T.P.]Final conditions
P1 = Initial pressure of the gas = 1 atmP2 = Final pressure of the gas = 0.5 atm
V1 = Initial volume of the gas = VV2 = Final volume of the gas = 2V
T1 = Initial temperature of the gas = 273 KT2 = Final temperature of the gas = ?

By Gas Law:

$\frac{\text{P}_1\times\text{V}_1}{\text{T}_1} = \frac{\text{P}_2\times\text{V}_2}{\text{T}_2}$

Substituting the values :

$$\begin{aligned}\frac{1\times \text{V}}{273} = \frac{0.5\times\text{2\text{V}}}{\text{T}_2} \\[0.5em] \text{T}_2 = 0.5\times 2 \times 273\\[0.5em] \text{T}_2 = 273\text{K}\end{aligned}$$

∴ Final temperature of the gas = 273 K = 0 °C

7(c)Section B

Classify the following types of reactions:

(i) 2Al + Fe2O3 ⟶ Al2O3 + 2Fe

(ii) 2KClO3 ⟶ 2KCl + 3O2

(iii) BaCl2 + Na2SO4 ⟶ BaSO4 + 2NaCl

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(i) Displacement reaction

(ii) Decomposition Reaction

(iii) Double Displacement Reaction

7(d)Section B

Mohr's salt has the formula (NH4)2SO4.FeSO4.6H2O

(i) Calculate its molecular mass.

(ii) What is the percentage of Nitrogen in Mohr's salt ? (Atomic mass: N =14, H = 1, S = 32, Fe = 56, O = 16)

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(a) Molar mass of Mohr's salt [(NH4)2SO4.FeSO4.6H2O]

= 2[14 + 4(1)] + 32 + 4(16) + 56 + 32 + 4(16) + 6[2(1) + 16]

= 2[18] + 32 + 64 + 56 + 32 + 64 + 6[18]

= 36 + 32 + 64 + 56 + 32 + 64 + 108

= 392 g

(ii) Molar mass of Mohr's salt [(NH4)2SO4.FeSO4.6H2O] = 392 g

Mass of nitrogen in one mole of Mohr's salt = 2 x 14 = 28 g

392 g Mohr's salt has mass of nitrogen = 28 g

∴ 100 g Mohr's salt will have mass

= $\frac{28 \times 100 }{392}$

= 7.14%

8(a)Section B

Write balanced chemical equations for the preparation of Hydrogen, when the following are used :

(i) Alkali

(ii) Non metal

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(i) Hydrogen from alkali

$\text{Zn} + 2\text{NaOH} \longrightarrow \underset{\text{[sodium zincate]}}{\text{Na}_2\text{ZnO}_2} + \text{H}_2 \text{[g]}$

(ii) Hydrogen from non-metal

$\underset{\text{hot coke}}{\text{C}} + \underset{\text{steam}}{\text{H}_2\text{O}} \xrightarrow{1000 ^{\circ} \text{C}} \underset{\text{water gas}}{[\text{CO} + \text{H}_2 ]} - \Delta$

8(b)Section B

What do you understand by ozone depletion ?

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Ozone layer depletion is the thinning of the ozone layer present in the upper atmosphere. This happens when the chlorine and bromine atoms in the atmosphere come in contact with ozone and destroy the ozone molecules

8(c)Section B

This question relates to the industrial manufacture of Hydrogen.

(i) Name the process.

(ii) Give the main reactions with conditions.

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(i) Bosch process

(ii) The main reactions of Bosch process are :

Step I

Reaction : Production of water gas

$\underset{\text{coke}}{\text{C}} + \underset{\text{steam}}{\text{H}_2\text{O}} \xrightarrow{1000 ^{\circ} \text{C}} \underset{\text{water gas}}{[\text{CO} + \text{H}_2 ]} - \Delta$

Step II

Reaction : Reduction of steam to hydrogen by carbon monoxide

$\underset{\text{water gas}}{[\text{CO} + \text{H}_2 ]} + \underset{\text{excess steam}}{\text{H}_2\text{O}} \xrightarrow[\text{Fe}_2\text{O}_3]{450 ^{\circ} \text{C}} \text{CO}_2 + 2\text{H}_2 + \Delta$

8(d)Section B

Write half reactions for the reaction — A+ + B ⟶ A + B+ and name the following:

(i) oxidizing agent

(b) substance oxidised

(c) reducing agent.

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Half reaction:

A+ + e- ⟶ A (Reduction)

B ⟶ B + e- (Oxidation)

a. A, as it is oxidizing B by accepting electrons.

b. B, as it is losing electrons.

c. B, as it is reducing A by providing electrons.

1(i)Section A

2H stands for :

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Two atoms of hydrogen gas

Reason — H represents the element hydrogen and prefix 2 shows 2 atoms of the element hydrogen.

1(ii)Section A

During an endothermic reaction:

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The temperature of surroundings decreases

Reason — Heat is absorbed during an endothermic reaction, hence the temperature of the surrounding will decrease.

1(iii)Section A

If pressure is doubled for a fixed mass of a gas, its volume will become:

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$\frac{1}{2}$ times

Reason — According to Boyle's law volume of a given mass of a dry gas is inversely proportional to its pressure at constant temperature.

Hence, if pressure is doubled for a fixed mass of a gas, its volume will become $\frac{1}{2}$ times

1(iv)Section A

When hydrochloric acid is added to silver chloride solution:

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No reaction takes place.

Reason — HCl + AgCl ⟶ no reaction

As the anion of both the reacts is same hence, no reaction is possible to form new products.

1(v)Section A

Elements X, Y and Z have atomic numbers 6, 9 and 12 respectively. Which of them will form a cation :

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Z

Reason — Z (12) = 2, 8, 2 forms a cation. It will lose its 2 electrons to achieve a stable electronic configuration thus forming a cation.

1(vi)Section A

The atomic numbers of elements A, B, C and D are 2, 6, 12 and 20 respectively. Which of them has 2 electrons in its N shell?

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D

Reason — The electronic configuration of D[20] = [2,8,8,2]. Hence, it has 2 electrons in its N shell.

1(vii)Section A

The number of atoms in a chloride ion is:

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One

Reason — The chloride ion [Cl-] has one atom.

1(viii)Section A

The acidic radical in Sulphurous acid is:

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SO3-2

Reason — An Acid radical is the radical that remains after an acidic molecule loses a hydrogen ion (H+). Hence, Sulphurous acid H2SO3, has SO3-2 as the acidic radical.

1(ix)Section A

When an oxygen ion is converted to an oxygen atom, it undergoes:

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Oxidation

Reason — When an oxygen ion O-2 having electronic configuration [2,8] is converted to an oxygen atom O having electronic configuration [2,6], it loses two electrons and hence undergoes oxidation.

1(x)Section A

The element whose atomic weight was corrected on the basis of its position in Mendeleev's periodic table is :

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Gold

Reason — Gold and Platinum are two elements whose atomic weights were corrected on the basis of their positions in Mendeleev's periodic table.

1(xi)Section A

An excessive release of carbon dioxide in the atmosphere is the cause of:

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Global warming

Reason — Carbon dioxide is a greenhouse gas and it traps heat radiated from the Sun. An excessive release of carbon dioxide in the atmosphere leads to rise in temperature, thus causing global warming.

1(xii)Section A

An element has 3 electrons in its M shell. It belongs to:

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Period III, group 13

Reason — The element having three shells [K, L, M] with three electrons in the valence shell is in group 13 [III A] and period 3. The name of the element is Aluminium.

1(xiii)Section A

Noble gases are monoatomic gases because:

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Their electronic configuration is stable

Reason — Noble gases have completely filled valence shell and so do not react with other elements and are therefore inert or unreactive hence, they are monatomic gases.

1(xiv)Section A

Rivers and lakes do not freeze easily because:

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Water has a high specific heat capacity and ice has a high latent heat of fusion.

Reason — Rivers and lakes do not freeze easily because the specific latent heat of fusion of ice is sufficiently high (= 336 J g-1). The water in lakes and rivers will have to liberate a large quantity of heat to the surrounding before freezing. The layer of ice formed over the water surface, being a poor conductor of heat, will also prevent the loss of heat from the water of lake, hence the water does not freeze all at once

1(xv)Section A

The type of reaction shown in the following equation is :

Cl2 + 2KBr ⟶ 2KCl + Br2

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Single displacement reaction

Reason — A chemical change in which a more active element displaces a less active element from its salt solution is called a single displacement reaction as shown above.

2(a)Section A

You are provided with a Periodic Table below :

What is this Periodic table known as? Give the Periodic Law for this Periodic table. Atomic Structure and Chemical Bonding, Concise Chemistry Solutions ICSE Class 9.

(i) What is this Periodic table known as?

(ii) Give the Periodic Law for the above Periodic table.

(iii) From the above Periodic table, predict the formula for the (i) oxide and (ii) hydride of Sulphur (S).

(iv) State one defect of this table.

(v) What is the basis of the Modern periodic table?

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(i) The table is known as Mendeleev's periodic table.

(ii) The Periodic Law for the above periodic table is that physical and chemical properties of elements are a periodic function of their atomic masses.

(iii) (i) SO3

(ii) SH2

(iv) One defect of this table was the grouping of chemically dissimilar elements. Elements such as copper and silver bear no resemblance to alkali metals (lithium, sodium, etc.) but they have been placed together in the first group.

(v) Modern periodic table is based on the Modern Periodic Law which states that — Physical and chemical properties of elements are periodic function of their atomic number.

2(b)Section A

Match the column A with column B:

Column AColumn B
(i) HydrogenA. Alkali metal
(ii) Boyle's lawB. Group I
(iii) SO2C. P-V relationship
(iv) SodiumD. Lead nitrate solution
(v) Hydrogen sulphideE. Produced by burning coal
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Column AColumn B
(i) HydrogenB. Group I
(ii) Boyle's lawC. P-V relationship
(iii) SO2E. Produced by burning coal
(iv) SodiumA. Alkali metal
(v) Hydrogen sulphideD. Lead nitrate solution
2(c)Section A

Complete the following sentences by choosing the correct answer from the bracket:

(i) The element below sodium in the Periodic Table is ............... , reactive than sodium. (more/less)

(ii) ............... is a gas having a triple bond (Nitrogen/Ammonia)

(iii) The average kinetic energy of the molecules of the gas is proportional to the ............... (absolute temperature/pressure)

(iv) If temperature is reduced to half, ............... would also reduce to half provided pressure remains constant. (volume/pressure)

(v) Ozone depletion is mainly caused by the active ............... atoms generated from CFC in the presence of UV radiation. (chlorine/fluorine)

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(i) The element below sodium in the Periodic Table is more, reactive than sodium.

(ii) Nitrogen is a gas having a triple bond.

(iii) The average kinetic energy of the molecules of the gas is proportional to the absolute temperature.

(iv) If temperature is reduced to half, volume would also reduce to half provided pressure remains constant.

(v) Ozone depletion is mainly caused by the active chlorine atoms generated from CFC in the presence of UV radiation.

2(d)Section A

(i) 20 g of NaCl is dissolved in 200 g of water. Calculate its concentration.

(ii) In order to make the concentration of alcohol 25%, how much alcohol is to be added to 150 cm3 of water?

(iii) Solubility of a substance at 45°C is 36.5g. What is meant by this statement?

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(i) Given,

solute = 20 g

solvent = 200 g

concentration = ?

Concentration of solution = $\frac{\text{Mass of solute}}{\text{\text{Mass of solute + Mass of solvent}}}$ x 100

Concentration of solution = $\frac{20}{\text{200 + 20}}$ x 100

= 9.09%

Hence, concentration = 9.09%

(ii) Given,

concentration = 25%

solvent = 150 cm3

solute = ?

Concentration of solution = $\frac{\text{Volume of solute}}{\text{\text{Volume of solute + Volume of solvent}}}$ x 100

$\frac{25}{100}$ = $\frac{\text{Volume of solute (x)}}{\text{\text{Volume of solute (x)+ 150 }}}$

$\frac{1}{4}$ = $\frac{\text{Volume of solute (x)}}{\text{\text{Volume of solute (x)+ 150 }}}$

4x = x + 150

3x = 150

x = 50 cm3

Hence, alcohol added = 50 cm3

(iii) Solubility of a substance at 45°C is 36.5g means that 36.5g of substance dissolves in 100 g of water at the temperature of 45°C.

2(e)Section A

(i) Give a balanced chemical equation for each of the following:

(ii) Give a balanced chemical equation for the following word equation:

Potassium dichromate reacts with sulphuric acid and sulphur dioxide to form potassium sulphate, chromium (III) sulphate and water.

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(i) Balanced chemical equation :

  1. 2Pb(NO3)2 $\xrightarrow{\space \Delta \space}$ 2PbO + 4NO2 + O2

  2. C2H5Br + NaOH ⟶ C2H5OH + NaBr

  3. 6CO2 + 12H2O ⟶ C6H12O6 + 6H2O + 6O2

(ii) K2Cr2O7 + H2SO4 + 3SO2 ⟶ K2SO4 + Cr2(SO4)3 + H2O

3(a)Section B

How will you distinguish between the following:

(i) Carbon dioxide gas and sulphur dioxide gas.

(ii) Hydrogen gas and hydrogen chloride gas?

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(i) Carbon dioxide gas has no effect on acidified potassium permanganate (KMnO4) and acidified potassium dichromate (K2Cr2O7) solution whereas sulphur dioxide gas turns acidified potassium permanganate from pink to clear colourless and acidified potassium dichromate from orange to clear green.

2KMnO4 + 2H2O + 5SO2 ⟶ K2SO4 + 2MnSO4 + 2H2SO4

K2Cr2O7 + H2SO4 + 3SO2 ⟶ K2SO4 + Cr2(SO4)3 + H2O

(ii) Hydrogen gas burns with a 'pop' sound in air whereas hydrogen chloride forms a curdy white ppt. on passage through AgNO3 solution. The precipitate dissolves in excess of NH4OH.

3(b)Section B

Write the basic and acidic radicals present in : Potassium plumbite.

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Potassium plumbite [K1+PbO22-] has basic radical [K1+] and acidic radical as [PbO22-]

3(c)Section B

(i) Name the process used to manufacture Hydrogen.

(ii) Write all the reactions involved (with proper conditions).

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(i) Bosch process

(ii) Reactions of Bosch process (with proper conditions):

Step I

Reaction : Production of water gas

$\underset{\text{hot coke}}{\text{C}} + \underset{\text{steam}}{\text{H}_2\text{O}} \xrightarrow{1000 ^{\circ} \text{C}} \underset{\text{water gas}}{[\text{CO} + \text{H}_2 ]} - \Delta$

Reactants : White hot coke and steam
Temperature : Around 1000°C
Process : Passage of steam over white hot coke [carbon]
Chamber : Specially designed convertor

Step II

Reaction : Reduction of steam to hydrogen by carbon monoxide

$\underset{\text{water gas}}{[\text{CO} + \text{H}_2 ]} + \underset{\text{excess steam}}{\text{H}_2\text{O}} \xrightarrow[\text{Fe}_2\text{O}_3]{450 ^{\circ} \text{C}} \text{CO}_2 + 2\text{H}_2 + \Delta$

Reactants : Water gas and excess steam
Temperature : Around 450 °C
Catalysts : Iron [III] oxide [Fe2O3], promoter chromic oxide [Cr2O3]
Process : Excess steam is mixed with water gas, passed over a catalyst at elevated temperature.
[CO is converted to CO2 with a further yield of hydrogen.]

Step III

Reactions : Separation of carbon dioxide and carbon monoxide from the above mixture

(a) CO2 is removed by dissolving mixture in water under pressure [30 atmospheres], or caustic potash solution to dissolve CO2.

2KOH + CO2 ⟶ K2CO3 + H2O

(b) CO is removed by dissolving mixture in ammoniacal cuprous chloride solution.

CuCl + CO + 2H2O ⟶ CuCl.CO.2H2O.

Thus, hydrogen gas is left over.

3(d)Section B

The question refers to the elements of the periodic table with atomic numbers from 3 to 18. In the table below, the elements are shown by letters which are not indicative of the usual symbols of the elements.

At. No.345678910
ElementABCDEFGH
At. No.1112131415161718
ElementIJKLMNOP

Which of these is :

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  1. H and P are nobles gases with fully filled valence shells.
  2. G and O are halogens having 7 electrons in their outermost orbit.
  3. D and L
4(a)Section B

Define Charles' law. Give its mathematical expression.

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Charles law states that pressure remaining constant, the volume of a given mass of dry gas increases or decreases by $\frac{1}{273}$ of its volume at 0°C for each 1°C increase or decrease in temperature, respectively.

Mathematical expression of Charles' law :

Suppose, a gas occupies V1 cm3 at T1 temperature and V2 cm3 at T2 temperature, then by Charles' law:

    V1 α T1

or V1 = kT1 (k is constant)

or $\frac{\text{V}_1}{\text{T}_1}$ = k and

    V2 α T2

or $\frac{\text{V}_2}{\text{T}_2}$ = k

∴ $\frac{\text{V}_1}{\text{T}_1}$ = $\frac{\text{V}_2}{\text{T}_2}$ = k (at constant pressure)

4(b)Section B

Give a scientific term for each of the following:

(i) When a substance absorbs moisture from the atmosphere and does not form a solution.

(ii) When a compound loses water of crystallization on exposure to dry air.

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(i) Hygroscopy

(ii) Efflorescence

4(c)Section B

Give a balanced chemical equation for the following :

(i) Exothermic reaction that is also a combination reaction.

(ii) A decomposition reaction involving salt of zinc.

(iii) A double decomposition reaction where a white precipitate is formed.

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(i) When carbon burns in oxygen to form carbon dioxide, lot of heat is produced. It is also a combination reaction.

C + O2 ↑ ⟶ CO2 ↑ + Heat

(ii) Zinc carbonate decomposes to form zinc oxide and releases carbon dioxide gas.

ZnCO3 $\xrightarrow{\space \Delta \space}$ ZnO + CO2 ↑

(iii) Formation of white precipitate of silver chloride on mixing sodium chloride solution and silver nitrate solution is a double decomposition reaction.

AgNO3 + NaCl ⟶ AgCl ↓ + NaNO3

4(d)Section B

Define a redox reaction. Give an equation and in it indicate the substance being oxidised and the substance being reduced.

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A chemical reaction which involves, oxidation of one substance and reduction of other substance is called a Redox Reaction.

Considering the reaction of Zinc with copper sulphate:

Zn + CuSO4 ⟶ ZnSO4 + Cu

Zn + Cu2+SO42- ⟶ Zn2+SO42- + Cu

Here, Zinc is oxidised and Copper is reduced.

Oxidation — Zn - 2e- ⟶ Zn2+
Reduction — Cu2+ + 2e- ⟶ Cu

5(a)Section B

(i) Name an element which does not form compound.

(ii) Give one example of Dobereiner's Triads.

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(i) Neon

(ii) Lithium, Sodium and Potassium

5(b)Section B

(i) What is the function of ozone in atmosphere ?

(ii) Name a salt whose solubility first increases and then decreases on increasing the temperature.

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(i) The ozone layer acts as a blanket in the atmosphere above 16 km from the earth’s surface. Ozone absorbs the harmful ultra-violet rays coming from the sun and prevents them from reaching the earth’s surface. Thus, it protects the life on earth from harmful effects of ultra-violet rays that can cause skin cancer and destroy many organisms necessary for life in general.

(ii) Hydrated Calcium Sulphate [CaSO4.2H2O]

5(c)Section B

It is found that on heating a gas, its volume increases by 50% and pressure decreases to 60% of its original value. If the original temperature was -15°C, find the temperature to which it was heated?

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Initial conditions [S.T.P.] :

P1 = Initial pressure of the gas = P
V1 = Initial volume of the gas = V
T1 = Initial temperature of the gas = -15°C = -15 + 273 = 258 K

Final conditions :

P2 (Final pressure) = pressure decreases to 60% of its original value

= $\frac{60}{100}$ of P

= $\frac{3}{5}$P

V2 (Final volume) = volume increases by 50% of its original value

= 1 + $\frac{50}{100}$ of V

= $\frac{100 + 50}{100}$ of V

= $\frac{150}{100}$ of V

= $\frac{3}{2}$V

T2 (Final temperature) = ?

By Gas Law:

$\frac{\text{P}_1\times\text{V}_1}{\text{T}_1} = \frac{\text{P}_2\times\text{V}_2}{\text{T}_2}$

Substituting the values :

$$\begin{aligned}\frac{\text{PV }}{258} = \frac{\frac{3}{5} \text{P}\times\frac{3}{2}\text{V}}{\text{T}_2} \\[1em] \text{T}_2 = \frac{3\times 3\times 258}{5 \times 2} = \frac{2322}{10} \\[1em] \text{T}_2 = 232.2 \text{K} \\[1em]\end{aligned}$$

∴ Final temperature of the gas = 232.2 - 273 = -40.8°C

5(d)Section B

(i) What causes the violence associated with torrential rain?

(ii) Which property of water enables it to modify the climate?

(iii) Explain why distilled water tastes flat.

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(i) The sudden release of latent heat of condensation causes the violence associated with torrential rain.

(ii) Due to it's high specific heat capacity, the presence of a large amount of water is able to modify the climate of the nearby land areas, making them warmer in winter and cooler in summer. Land and sea breezes also take place because of this great moderating property of water.

(iii) Pure water is tasteless. The taste in water is due to the gases and solids dissolved in it i.e., impurities present in it. As boiled and distilled water are pure containing no impurities hence they taste flat i.e., are tasteless.

6(a)Section B

Give a balanced chemical equation for the following:

(i) Laboratory preparation of hydrogen.

(ii) Preparation of hydrogen from an alkali.

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(i) Laboratory preparation of hydrogen

Zn + 2HCl ⟶ ZnCl2 + H2 ↑

(ii) Hydrogen from alkali

$\text{Zn} + 2\text{NaOH} \longrightarrow \underset{\text{[sodium zincate]}}{\text{Na}_2\text{ZnO}_2} + \text{H}_2 \text{[g]}$

6(b)Section B

Draw the solubility curve for KNO3 and CaSO4.

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The solubility curves for KNO3 and CaSO4 are shown below:

Draw the solubility curve for KNO3 and CaSO4. Water, Concise Chemistry Solutions ICSE Class 9.
6(c)Section B

Name any two impurities present in the hydrogen gas prepared in the laboratory. Also name the chemical used to remove any one impurity that you have stated.

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Two impurities present in the hydrogen gas prepared in the laboratory are :

  1. Hydrogen sulphide (H2S)
  2. Sulphur dioxide (SO2)

Lead nitrate solution is used to remove hydrogen sulphide.

6(d)Section B

Draw the shell diagram for the formation of bond between Hydrogen and Nitrogen. Name the compound formed.

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Hydrogen and Nitrogen combine to form ammonia [NH3].

Atomic orbit structure diagram for formation of ammonia molecule is shown below:

Draw the atomic orbit structure diagram for formation of a ammonia molecule. Chemical Bonding, Simplified Chemistry Dalal Solutions ICSE Class 9
7(a)Section B

Give one importance each of dissolved salts and dissolved gases in water.

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One importance of dissolved salts in water is that the dissolved salts supply the essential minerals needed for the growth and development of plants.

One importance of dissolved gases in water is that aquatic plants make use of dissolved carbon dioxide for photosynthesis, i.e., to prepare their food.

7(b)Section B

Give one observation when potassium is added to water. Also give the balanced chemical equation.

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When potassium is added to water, the metal melts and moves very quickly on the surface of the water. The metal ignites along with hydrogen gas, hence, sparks along with lilac flame is visible.

2K + 2H2O ⟶ 2KOH + H2

7(c)Section B

(i) List one property in which hydrogen resembles alkali metals and one property in which hydrogen resembles halogens.

(ii) Also list a property in which hydrogen differs from both alkali metals and halogens.

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(i) Both alkali metals and hydrogen act as reducing agents.

CuO + H2 ⟶ Cu + H2O

CuO + 2Na ⟶ Cu + Na2O

Both halogens and hydrogen are non-metals. They show electronegative character.

H + e- ⟶ H-

F + e- ⟶ F-

(ii) Hydrogen atom has only one shell but alkali metal and halogens have two or more shells.

7(d)Section B

(i) State any one reason for discarding 'Law of Octaves'.

(ii) What is periodicity? Explain the cause of periodicity.

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(i) The Newland's law of Octaves did not work with heavier elements i.e., those lying beyond Calcium. As more and more elements were discovered, they could not be fitted into Newland's Octaves. Hence, this law was discarded.

(ii) The phenomenon of occurrence of characteristic properties of elements at definite intervals in the modern periodic table when elements are arranged in increasing order of their atomic numbers is called periodicity.

Reasons for Periodicity is — after definite intervals of atomic number, similar valence shell electronic configuration occurs and as properties of elements depend upon the arrangement of electrons in various shells including valence shells, hence periodicity in properties occur.

8(a)Section B

How is the lightest gas collected and dried during its laboratory preparation?

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The lightest gas, hydrogen is collected by downward displacement of water.

To dry the gas common drying agents like fused calcium chloride, caustic potash stick and phosphorus pentoxide can be used.

After purifying and drying, the gas is collected over mercury because mercury has no reaction with it.

8(b)Section B

Name the first three Halogen. State their physical appearance.

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ElementPhysical stateColour
Fluorine (F)GasPale yellow
Chlorine (Cl)GasGreenish yellow
Bromine (Br)LiquidReddish brown
8(c)Section B

Draw the shell diagram to explain the bond formation between an alkali metal and the halogen of the third period.

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Below diagram shows the bond formation between an alkali metal Sodium and a halogen Chlorine to form Sodium chloride [NaCl]:

Draw orbit structure diagram of sodium chloride (NaCl). Atomic Structure and Chemical Bonding, Concise Chemistry Solutions ICSE Class 9
8(d)Section B

Explain the following assertions:

(i) Composition of dissolved air in water is different from ordinary air.

(ii) Steam at 100°C burns more severely than water at 100°C.

(iii) It is necessary to compare gases at STP.

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(i) Ordinary air contains 78% nitrogen, 21% oxygen and 0.01% carbon dioxide. But oxygen is more soluble in water as compared to nitrogen. Hence, the composition of air dissolved is different from ordinary air.

The composition of air dissolved in water is 33% oxygen, 66% nitrogen and 1% carbon dioxide.

(ii) Steam has a higher heat content on account of high specific latent heat of condensation that is 2268 J g-1. Hence, steam at 100°C carries more heat than water. Therefore, steam at 100°C burns more severely than water at 100°C.

(iii) Since volume of a gas changes remarkably with change in temperature and pressure, it becomes necessary to choose standard values of temperature and pressure to which gas volumes can be referred.

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