(a) From the table, the solubility of KNO3 at 313 K is 62 g per 100 g of water.
62 g of KNO3 per 100 g of water
Mass of solute per 50 g of water is
= $\frac{62}{100}$ x 50
= 31 g
∴ Mass of solute per 50 g of water is 31 g.
(b) The solubility of KCl at 353 K is 54 g per 100 g of water.
The solubility of KCl at 293 K (room temperature) is 35 g per 100 g of water.
When the solution cools, the solubility decreases.
The excess KCl will precipitate out of the solution as crystals.
(c) Considering given salts are dissolved in 100g of water
Solubility of KNO3 at 293 K
Mass of solute = 32 g
Mass of solvent = 100 g
Solubility = $\frac{\text{Mass of solute}}{\text{Mass of solvent}}$ x 100
= $\frac{32}{100}$ x 100
= 32 g
∴ Solubility of KNO3 at 293 K is 32 g.
Solubility of NaCl at 293 K
Mass of solute = 36 g
Mass of solvent = 100 g
Solubility = $\frac{\text{Mass of solute}}{\text{Mass of solvent}}$ x 100
= $\frac{36}{100}$ x 100
= 36 g
∴ Solubility of NaCl at 293 K is 36 g.
Solubility of KCl at 293 K
Mass of solute = 35 g
Mass of solvent = 100 g
Solubility = $\frac{\text{Mass of solute}}{\text{Mass of solvent}}$ x 100
= $\frac{35}{100}$ x 100
= 35 g
∴ Solubility of KCl at 293 K is 35 g.
Solubility of NH4Cl at 293 K
Mass of solute = 37 g
Mass of solvent = 100 g
Solubility = $\frac{\text{Mass of solute}}{\text{Mass of solvent}}$ x 100
= $\frac{37}{100}$ x 100
= 37 g
∴ Solubility of NH4Cl at 293 K is 37 g.
(d) From the table, when we calculate the solubility of KNO3 at 283 K,
Mass of solute = 21 g
Mass of solvent = 100 g
Solubility = $\frac{\text{Mass of solute}}{\text{Mass of solvent}}$ x 100
= $\frac{21}{100}$ x 100
= 21 g
Whereas, the solubility of NaCl, KCl and NH4Cl will be 36 g, 35 g and 24 g respectively.
Hence, the least solubility will be of KNO3 at 283 K
(e) The solubility of most salts in water usually increases with rise in temperature. Example, Potassium nitrate.
There are some salts which show anomalous solubility. Their solubility first increases, and then decreases, with rise in temperature.
Example: Na2SO4.10H2O (Glauber's salt).
Solubility curve of Na2SO4.10H2O rises till it reaches 32.8°C, and then it falls slightly. This is because Na2SO4.10H2O is hydrous below 32.8°C and loses its water and becomes anhydrous above 32.8°C.