1(xv)
The solution set for the inequation 2x + 4 ≤ 14, x ∈ W is :
- (a){1, 2, 3, 4, 5}
- (b){0, 1, 2, 3, 4, 5}
- (c){1, 2, 3, 4}
- (d){0, 1, 2, 3, 4}
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Solving,
⇒ 2x + 4 ≤ 14
⇒ 2x ≤ 14 - 4
⇒ 2x ≤ 10
⇒ x ≤ $\frac{10}{2}$
⇒ x ≤ 5.
Since, x ∈ W,
∴ x = {0, 1, 2, 3, 4, 5}.
Hence, Option 2 is the correct option.