1(vii)
The given table shows the distance covered and the time taken by a train moving at a uniform speed along a straight track.
| Distance (in m) | Time (in sec) |
|---|---|
| 60 | 2 |
| 90 | x |
| y | 5 |
The values of x and y are :
- (a)x = 4, y = 150
- (b)x = 3, y = 100
- (c)x = 4, y = 100
- (d)x = 3, y = 150
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Speed = $\frac{\text{Distance}}{\text{Time}}$
Average speed = $\frac{60}{2}$ = 30 km/hr
$$\begin{aligned}\Rightarrow \frac{90}{x} = 30 \\[1em] \Rightarrow x = \frac{90}{30} = 3. \\[1em] \phantom{\Rightarrow} \frac{y}{5} = 30 \\[1em] \Rightarrow y = 30 \times 5 = 150.\end{aligned}$$
Hence, Option 4 is the correct option.