The n th term of an Arithmetic Progression (A.P.) is given by the relation T n = 6(7 - n). Find ∶

(a) T_n = 6(7 - n)

Substituting n = 1, we get :

T₁ = 6(7 - 1) = 6 × 6 = 36.

Substituting n = 2, we get :

T₂ = 6(7 - 2) = 6 × 5 = 30.

Common difference (d) = T₂ - T₁

= 30 - 36 = -6.

Hence, common difference (d) = -6 and first term = 36.

(b) By formula,

Sum upto n terms = $\frac{n}{2}[2a + (n - 1)d]$

$$\begin{aligned}\text{Sum upto 25 terms} = \frac{25}{2}[2 \times 36 + (25 - 1) \times -6] \\[1em] = 12.5 \times [72 + 24 \times -6] \\[1em] = 12.5 \times [72 - 144] \\[1em] = 12.5 \times -72 \\[1em] = -900.\end{aligned}$$

Hence, sum of its first 25 terms = -900.