1(viii)
A bag contains 3 red and 2 blue marbles. A marble is drawn at random. The probability of drawing a black marble is :
- (a)0
- (b)$\frac{1}{5}$
- (c)$\frac{2}{5}$
- (d)$\frac{3}{5}$
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Since, there is no black marble in the bag.
∴ Probability of drawing a black marble = 0.
Hence, Option 1 is the correct option.