Assertion (A): If $\sec\theta + \tan\theta = a$ and $\sec\theta - \tan\theta = b$ then $ab = 1$.

ICSE Class 10 Mathematics PYQ · 2027 Specimen · Section A

1(xiii)1 Mark · 2027 · Section A · 2027 Specimen

Assertion (A): If $\sec\theta + \tan\theta = a$ and $\sec\theta - \tan\theta = b$ then $ab = 1$.

Reason (R): $\sec^2\theta - \tan^2\theta = 1$

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Given,

$$\begin{aligned}\Rightarrow \sec\theta + \tan\theta = a \\[1em] \Rightarrow \sec\theta - \tan\theta = b \\[1em] \Rightarrow ab = (\sec\theta + \tan\theta)(\sec\theta - \tan\theta) \\[1em] \Rightarrow ab = \sec^2\theta - \tan^2\theta \\[1em] \Rightarrow ab = 1\end{aligned}$$

So assertion (A) is true.

We know that,

⇒ $\sec^2\theta - \tan^2\theta = 1$

This is a fundamental trigonometric identity.

Thus, Both (A) and (R) are true and (R) is the correct explanation of (A).

Hence, option 3 is the correct option.

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