An electric bulb of resistance 500 Ω, draws a current of 0.4 A. Calculate the power of the bulb and the potential difference at it's end.

ICSE Class 10 Physics PYQ · 2017 Paper · Section I

4(a)2 Marks · 2017 · Section I · 2017 Paper

An electric bulb of resistance 500 Ω, draws a current of 0.4 A. Calculate the power of the bulb and the potential difference at it's end.

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Given,

R = 500 Ω,

I = 0.4 A

Power of bulb P = I2 R
= (0.4)2 x 500 = 80 W

Potential difference at the ends of the bulb V = IR = 0.4 x 500 = 200 V

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