6(iii)
If a wire of resistance 2Ω gets stretched to thrice its original length :
(a) Calculate the new resistance of the wire.
(b) What happens to the specific resistance of the wire?
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(a) Given, R = 2Ω
⇒ ρ$\frac{\text{l}}{\text{A}}$ = 2Ω
Let new resistance be R'.
New length = $3\text{l}$
New Area = $\frac{\text{A}}{3}$
∴ R' = ρ$\frac{\text{3l}}{\frac{\text{A}}{3}}$
= ρ$\frac{\text{9l}}{\text{A}}$
= 9R = 9 × 2 = 18Ω
Hence, new resistance = 18Ω
(b) Specific resistance of the wire remains unchanged since it does not depend on the dimensions of the wire. It is the characteristic property of the substance.