1(i)
Centre of gravity of the given square PQRO lies at:

- (a)(2, –2)
- (b)(3, –2)
- (c)(–2, 2)
- (d)(–2, 1)
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(2, –2)
Reason — As given figure is a square with side length of 4 units which is a uniform shape so it's centre of gravity lies on the point of intersection of it's diagonals and since diagonals of a square are equal to each other then it's centre of gravity lies on it's geometrical centre.
So,
Coordinates of C.G. = Coordinates of geometrical centre of the square PQRO = (2,-2)