Akash takes a uniform metre scale and suspends a weight of 2 N at one end ‘X’, and a weight of 5 N on the other end ‘Y”. He then balances the ruler horizontally on a knife edge placed at 70 cm from X. Draw a diagram of the arrangement and calculate the weight of the ruler.
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The diagram of the arrangement is shown below :
Given,
Weight at the end X (W1) = 2 N
Weight at the end Y (W2) = 5 N
Distance of X from the knife (R1) = 70 cm
Distance of Y from the knife (R2) = 100 cm - 70 cm = 30 cm
Let,
W = weight of the scale
Now,
Anticlockwise moment (due to 2N) = R1 x W1 = 2 × 70 = 140 Nm
Clockwise moment (due to 5N) = R2 x W2 = 5 × 30 = 150 Nm
Anticlockwise moment (due to weight of the scale) = W × 20 = 20 W
For equilibrium,
Anticlockwise moment of force about knife = Clockwise moment of force about knife
$$\begin{aligned}150 = 140 + 20\text { W} \\[1em] 20 \text W = 150 - 140 = 10 \\[1em] \text W = \frac{10}{20} = 0.5\ \text N\end{aligned}$$
So, weight of the scale is 0.5 N.