A type of glass block has a refractive index of 1.8.
(a) Calculate the speed of light in this glass. (Given speed of light in air 3 x 108 m s-1)
(b) If the width of this block is doubled, then what will be the speed of light in the block?
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(a) Given,
- Refractive index of the glass block = 1.8
- Speed of light in air = 3 x 108 m s-1
As, refractive index (μ) of the glass block is given by,
$$\begin{aligned}\text μ = \frac{\text {Speed of light in vacuum or air}}{\text {Speed of light in the glass block}} \\[1em] \Rightarrow \text {Speed of light in the glass block} = \frac{\text {Speed of light in vacuum or air}}{\text μ} \\[1em] = \frac{3\times 10^8}{1.8} \\[1em] = \frac{30\times 10^8}{18} \\[1em] = \frac{5\times 10^8}{3} \\[1em] \approx 1.67 \times 10^8 \text { m s}^{-1}\end{aligned}$$
Hence, speed of light in the glass block is approximately 1.67 x 108 m s-1.
(b) If the width of the glass block is doubled, the speed of light does not change because the speed of light in a medium depends only on the refractive index of the material, not on its thickness or width.
Therefore, the speed remains 1.67 x 108 m s-1.