A door lock is opened by turning the lever (handle) of length 0.2 m. If the moment of force produced is 1 Nm, then the minimum force required is:

5 N

Reason —

Given,

Length of lever = Perpendicular distance of the line of action of the force = 0.2 m
Moment of force = 1 Nm
As, Moment of force = Force × Perpendicular distance of the line of action of the force

1 = force x 0.2

force = $\frac{1}{0.2}=\frac{10}{2}$ = 5 N